ࡱ;  R Fx.j@CompObj\WordDocument;(ObjectPoolx.jx.j FMicrosoft Word 6.0 DocumentNB6WWord.Document.6;  Oh+'0  ! -9A IUr z5Science F:Microsoft Office:Microsoft Word 6:chem labLAB: TITLE OF LABsciencescience'@j@)j@".j@ܥhO e;(""#####4v$v$v$v$v$$ $v$'f$$$$$$$$&&&&&&&&|'X'g'#$ $@$$$'$##$$$$$$#$#$&2$@$6####$&$$Lab: Specific Heat of Solids  Introduction Chemists identify substances on the basis of their chemical and physical properties. One physical property of a substance isthe amount ofheat energy it will absorb per unit of mass. This property can be measured quite accurately and is called the specific heat. Specific heat is the amount of heat energy, measured in joules, needed to raise the temperature of one gram of the substance one Celsius degree. Often applied to metallic elements, specific heat can be used as a basis for comparing energy absorption and transfer. To measure specific heat in the laboratory, a calorimeter of some kind must be used. A calorimeter is a well-insulated container used in measuring energy changes. The calorimeter is insulated to reduce the loss or gain of heat energy from from the surrounding room conditions. Heat energy always flows from an object at a higher temperature to an object at a lower temperature. The heat gained by the cooler substance equals the heat lost by the warmer substance, ifwe assume no loss of heat to the surrounding environment. heat lost = heat gained In this experiment, you will determine the specific heat of 3 metal samples. The metal sample will be heated to a high temperature in a water bath then placed into a calorimeter containing a known quantity of water at a lower temperature. Having measured the mass of the water in the calorimeter, the temperature change of the water (T), and knowing the specific heat of water (4.184 J/g.oC), the heat gained by the water (lost by the metal) can be calculated as follows: heat gained by water = mass of water X specific heat of water X (T) of water The heat gained by the water was the heat lost by the metal. Therefore, heat lost by metal = mass of metal X SPECIFIC HEAT OF METAL x (T) of metal The only unknown in this equation is the SPECIFIC HEAT OF THE METAL which can be calculated. MATERIALS thermometer clamp test tube 250 mL beaker iron ring styrofoam cup wire gauze 3 metal samples ring stand Procedure 1. Fill a 250 mL beaker about half full of water. Place the beaker of water on a ring stand with wire gauze. Prepare to heat this water. 2. Measure and record the mass of an empty medium size test tube.. 3. Add the sample metal pieces until the test tube is half full. Measure and record the mass of the test tube with the metal. 4. Place the test tube in the beaker of water and clamp it in place. Begin heating until the water is boiling. Boil for 2 minutes. 5. While the metal is heating obtain a foam cup. Measure and record its mass. Fill the cup half full of water. Measure and record its mass.. 6. Take and record the temperature of the water in the foam cup. 7. When the metal has been boiling for 2 minutes, loosen the clamp and quickly, but carefully, pour the metal all at once into the foam cup. Stir gently and record the highest temperature reached in the cup. 8. Repeat this procedure for 2 more metal samples. Data MASS DATA METAL #1METAL #2METAL #3TEST TUBETEST TUBE + METALSTYROFOAM CUPSTYROFOAM CUP + WATER temperature data METAL #1METAL #2METAL #3BOILING WATERWATER IN CUPWATER IN CUP AFTER METAL IS ADDED Calculations 1. Calculate the heat gained by the water in the styrofoam cup. Remember that HEAT GAINED = amount of water x specific heat x change in temeprature 2. RECALL THAT THE HEAT GAINED BY THE WATER IS EQUAL TO THE HEAT LOST BY THE METAL. You know the mass of metal and the temperature change of the metal (the temperature change is boiling water (100) down to the final temperature of the water in the calorimeter). The only information you do not have is the specific heat of the metal which you can now calculate. HEAT = MASS OF METAL x SPECIFIC HEAT x CHANGE IN LOST BY OF METAL TEMPERATURE OF METAL METAL Analysis Write a conclusion. Include the specific heats you calculated for the three metals in this lab. STATES OF MATTER: HEATS Name: _______________________ Partner #1: _______________________ Partner #2: _______________________ Acton-Boxborough Regional High School Due Date: ______________________ Acton-Boxborough Regional High School  |HH(EG(HH(d'`|HH(EG(HH(d'` |HH(EG(HH(d'`00&ta0`0(00&00&00&00&00&ࡱ; SummaryInformation(Microsoft Word 6.0.18ࡱ;  -'4 #   " devw 8@mnwZuU]cU]cU]]uD]a UZ]c( UZ]c(1-.@AQRlmH I 5 6   " # q $$$,$$$$$$$$$$$$$$$$$$$$$$$$$$$,h*   !"#$%34567MNOPQRcdenw$,$,$,$,$,$,$,,,,,,,,,,,,,,,,,,,,,,,,,,$,$,$,l H$(+,vwy&Uklmw$$,$,$$$$$$$$$$$$$$$,$0h !shl H$#4YZ$T$T$$$h 0 !l h !s K@Normal]a .@. Heading 1 < U]ck,@, Heading 2 < UV]c*@* Heading 3 <U]c"A@"Default Paragraph Font @ Header ! @ Footer !/@Listh*O"* Chem HeaderL UZ]c2@2List 23@BList 38$D@R$ List ContinuehxB@b Body Textx# \q#    m{ ;kscience=Science F:Teacher Folders:Murphree:Specific Heat Lab-liquids science5Science F:Teacher Folders:Murphree:Sp. Ht. Lab-solidsscience5Science F:Teacher Folders:Murphree:Sp. Ht. Lab-solidsscience5Science F:Teacher Folders:Murphree:Sp. Ht. Lab-solidsscience5Science F:Teacher Folders:Murphree:Sp. Ht. Lab-solidsscience5Science F:Teacher Folders:Murphree:Sp. Ht. Lab-solidsscience5Science F:Teacher Folders:Murphree:Sp. Ht. Lab-solidsscience5Science F:Teacher Folders:Murphree:Sp. Ht. Lab-solids@_ _ _ @ fMTimes New Roman Symbol MArial MTimesMNew Century SchlbkMHelvetica"1hcJ3FOK3F%K3F*!g4Science F:Microsoft Office:Microsoft Word 6:chem labLAB: TITLE OF LABsciencescienceࡱ;